(4x+4)^2=(3x+24)(3x+3)

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Solution for (4x+4)^2=(3x+24)(3x+3) equation: 



(4x+4)^2=(3x+24)(3x+3)

We move all terms to the left:

(4x+4)^2-((3x+24)(3x+3))=0

We multiply parentheses ..

-((+9x^2+9x+72x+72))+(4x+4)^2=0



We calculate terms in parentheses: -((+9x^2+9x+72x+72)), so:

(+9x^2+9x+72x+72)

We get rid of parentheses

9x^2+9x+72x+72

We add all the numbers together, and all the variables

9x^2+81x+72

Back to the equation:

-(9x^2+81x+72)



We get rid of parentheses

-9x^2-81x+(4x+4)^2-72=0

We move all terms containing x to the left, all other terms to the right

-9x^2-81x+(4x+4)^2=72

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